By Arijit Saha, Nilotpal Manna

ISBN-10: 1934015032

ISBN-13: 9781934015032

Scholars and training engineers obtain a easy creation to the typical tools used to layout electric circuits utilizing smooth common sense layout strategies, so will locate this an strange mixture of conventional teachings up to date with sleek good judgment sequencing and computer-aided instruments. it really is designed as a textbook, so college-level scholars and training engineers will locate it such a lot convenient - however it covers all of the fundamentals, from Boolean algebra and common sense gates to Karnaugh maps. An accompanying cd-rom comprises simulations and third-party software program, making this hugely steered for any in-depth, working towards engineer or scholar.

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**Additional resources for Digital Principles and Logic Design (Engineering) (Computer Science) (Engineering Series)**

**Sample text**

18. Use the (a) 6-bit internal code, (b) 7-bit ASCII code, and (c) 8-bit EBCDIC code to represent the statement: P = 4*Q Solution. 19. Express the following decimal numbers as 2421 codes: (a) 168 (b) 254 (c) 6735 Solution. 20. Express the following 2421 codes as decimal numbers: (a) 1110 1011 1101 (b) 0010 1100 0001 (c) 1011 0100 1111 (d) 1101 1111 1011 Solution. 1 Express the following decimal numbers in Excess-3 code form: (a) 245, (b) 739, (c) 4567, and (d) 532. 2 Express the following Excess-3 codes as decimals: (a) 100000110110, (b) 0111110010010110, and (c) 110010100011.

To get the true result we have to discard the carry and make the 8’s complement of the result obtained and put a negative sign before the result. 9 9’s AND 10’s COMPLEMENT ARITHMETIC The 9’s complement of a decimal number can be found by subtracting each digit in the number from 9. The 10’s complement can be obtained by subtracting the LSB from 10 and the rest of each digit in the number from 9. 6. 6 Decimal digit 9’s complement 10’s complement 0 9 10 1 8 9 2 7 8 3 6 7 4 5 6 5 4 5 6 3 4 7 2 3 8 1 2 9 0 1 24 DIGITAL PRINCIPLES AND LOGIC DESIGN The method of subtraction using 9’s complement method is the same as 1’s complement method in a binary system.

A) (b) 0011 1000 1010 0100 (c) 0101 1001 0011 Excess-3 code is 0101 1011 1100 0111 Subtracting 3 from each digit –0011 –0011 –0011 –0011 0010 1000 1001 0100 2 8 9 4 0011 1000 1010 0100 –0011 –0011 –0011 –0011 0000 0101 0111 0001 0 5 7 1 BCD number is Decimal number is Hence the decimal number is 2894. (b) Excess-3 code is Subtracting 3 from each digit BCD number is Decimal number is Hence the decimal number is 571. (c) Excess-3 code is Subtracting 3 from each digit BCD number is 0101 1001 0011 –0011 –0011 –0011 0010 0110 0000 2 6 0 Decimal number is Hence the decimal number is 260.

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